3x^2-35=2317

Solution for 3x^2-35=2317 equation:

3x^2-35=2317

We move all terms to the left:

3x^2-35-(2317)=0

We add all the numbers together, and all the variables

3x^2-2352=0

a = 3; b = 0; c = -2352;
Δ = b2-4ac
Δ = 02-4·3·(-2352)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*3}=\frac{-168}{6}
=-28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*3}=\frac{168}{6}
=28
$